Chapter 10

The Schwarzschild Black Hole

Return to Modern Relativity

10.1 The Schwarzschild Solution

This section will present a simple derivation for the Schwarzschild solution of general relativity and then derive perihelion procession.

(10.1.1) 

In spherical coordinates, but otherwise flat space-time the invariant interval took the form:

ds2 = dct2 - dr2 - r2dq 2 - r2sin2qdf2

Let's examine the slightly more general possibility that a vacuum field solution exists in the form:

ds2 = A(r)dct2 - A-1(r)dr2 - r2dq 2 - r2sin2qdf2

(10.1.2)

Then:

g00 = A, g11 = -A-1, g22 = -r2, g33 = -r2sin2q and all other gmn = 0.

Recalling Eqn. 4.3.3

grngns = drs

its obvious that:

g00 = A-1, g11 = -A, g22 = -r -2, g33 = -r -2sin -2q and all other gm n = 0.

 111

 

112 Chapter 10 The Schwarzschild Black Hole

From the equation for the affine connection Eqn. 4.4.3

Glmn = (1/2)gls(gsm ,n + gsn ,m - gmn ,s)

the following can be calculated:

G 000 = G 011 = G 101 = G 110 = 0.

G 122 = -rA

G 212 = G 221 = G 313 = G 331 = 1/r

G 233 = -sinq cosq

G 323 = G 332 = cotq

G 133 = -rAsin2q

Plugging these into the Ricci tensor of general relativity Rmn, Eqn.6.3.1 from Eqn.6.3.3 outcome in the following:

and all other Rmn = 0.

 

10.1 The Schwarzschild Solution 113

For the case that space is vacuum Tmn = 0 except for the possibility of mass at the origin, and if we take

l » 0, then according to Eqn. 6.3.21 we have

Rmn = 0.

This is satisfied with the expressions we arrived at for the Ricci tensor components if

Let:

Then:

Separating variables and integration results in:

where r0 is a constant of integration.

So:

Separating variables and integrating again results in:

where b is another integration constant.

 

114 Chapter 10 The Schwarzschild Black Hole

So:

(10.1.3)

In the limit as r goes to infinity space-time goes flat and the solution should therefor become that for special relativity, Therefor b = 1.

So:

So ds can be written:

(10.1.4)

In a weak field limit we should have g00 = 1 + 2f /c2 where f is the Newtonian gravitational potential. For a point mass at the origin this should be f = - GM/r What we have is g00 = r0/r. Relating the two results in

(10.1.5)

Therefor the integration constant r0 which is a parameter describing this spacetime geometry is what we think of as mass.

For a black hole r0 is called the Schwarzschild radius. The Schwarzschild solution of general relativity is the solution for the case of a non-rotating uncharged black hole. The Schwartzschild radius describes a mathematical surface at which there is also a coordinate singularity for this kind of black hole.

 

 

10.1 The Schwarzschild Solution 115

The coordinate singularity for general relativity is a place where infinities appear in our equations due to our choice of coordinates such as the

term has at r = r0 , but locally no physical quantities are infinite. In general relativity this surface is called an event horizon. Most generally an event horizon is any surface at which the coordinate speed of light vanishes.

Now lets derive perihelion procession.

 The Schwarzschild solution is independent of both ct and f yielding two Killing four-vectors

T = ect, and F = ef.

The first gives us the following conserved quantity for geodesic motion called the energy parameter for which we define g by

gc = gmnTmUn

gc = g00T0U0

gc = g00(dct/dt)

 

(10.1.6)

The second killing four-vector results in another conserved quantity for geodesic motion called the angular momentum parameter, lz = Lz/m

- lz = gmnFmUn

- lz = gffFfUf

lz = - gff(df/dt)

 

(10.1.7)

Inserting these into the Schwarzschild solution itself and dividing through by dt2 results in

(10.1.8)

Orient the equatorial plane to match the orbit so q = p/2.

(10.1.9)

With a little algebra we wind up with equations of motion that look very Newtonian

(10.1.10)

(10.1.11)

the difference being that the relativistic expression corresponding to conservation of energy here has a term that looks like a 1/r3 potential, or a 1/r4 force. Using the second in the first

 

(10.1.12)

Changing variables to u = 1/r

(10.1.13)

Differentiate with respect to u and chain rule

(10.1.14)

Simplify

(10.1.15)

Its a strait forward back check to verify neglecting terms in the check above first order in (GM/c2) the following expression satisfies that differential equation

(10.1.16)

And so works as an approximate solution for a weak field.

The perihelions now occur at

(10.1.17)

or

(10.1.18)

If the period of the orbit is T, then the total change in angle for the location of perihelion over time is then

(10.1.19)

or in terms of the length of the semi-major axis a:

(10.1.20)

 

Exercises

Problem 10.1.1

Verify that far from the hole, the Schwarzschild solution obeys Eqn. 9.2.4 to order 1/r2. Why needn't all f ii obey the Poisson equation or the inhomogenous wave equation Eqn. 9.2.3 for a delta function source?

Problem 10.1.2

Other constant values for b in Eqn. 10.1.3 besides 1 also result in vacuum field solutions. Why should they not correspond to "exterior" solutions?

Problem 10.1.3

There are two concentric thin spherical mass shells. One is radius R1 and mass M1 and the other is radius R2 and mass M2. Use b - r0/r = 1 + 2f /c2 where f is the Newtonian potential, to model the spacetime by Eqn 10.1.3 for each vacuum region. What should b and r0 be in the region r less than R1, r between R1 and R1, and r greater than R1? (It turns out this is a bad model for thick shells because g11 takes on an odd behavior. For a fluid sphere g11 goes back to -1 at the origin.)

Problem 10.1.4

Look up recent solar system data and use equation 10.1.20 to find Dfp for the mercury's procession after 100 of Earth's years. (Note - It is actually 575", but 534" are accounted for by the effect of other planets.)

___________________________________________________________________________________________

116 Chapter 10 The Schwarzschild Black Hole

10.2 Hovering over a Schwarzschild Black Hole

In this section we derive the equation for the amount of force felt by an object held stationary over a Schwarzschild black hole for general relativity.

F'1felt = (1 - 2GM/rc2)-1/2GMm/r2

(10.2.1)

and then mention why we see from this that the assumption that we could hold it stationary underneath the event horizon was false.

Start four-acceleration Eqn. 5.3.1

Al = dUl/dt + GlmnUmUn

The only nonzero Um is Uct resulting in

Al = dUl/dt + GlctctUctUct

We then insert Uct = dct/dt = c(1 - 2GM/Rc2)-1/2

Al = dUl/dt + Glctctc2(1 - 2GM/Rc2)-1

The only nonzero Al is Ar

Ar = Grctctc2(1 - 2GM/Rc2)-1

We then insert the affine connection

Ar = (1/2)grr(-gctct,r)c2(1 - 2GM/Rc2)-1

resulting in

Ar = GM/r2

We then insert this into equation Eqn.5.2.2

|F| = m(-gmnAmAn)1/2

resulting in

|F| = m[(1-2GM/rc2)-1(GM/r2)( GM/r2)]1/2

Which simplifies to Eqn.10.2.1

|F| = (1-2GM/rc2)-1/2GMm/r2

This is the amount of force felt by the object hovering over the hole for general relativity. We should note that it

 

10.2 Hovering over a Schwarzschild Black Hole 117

becomes infinite at the event horizon and imaginary underneath and therefor the very assumption that an object underneath the event horizon of a Schwarzschild black hole could be held still was false.

Exercises

Problem 10.2.1

Consider a cable lowering an observer of m down to the event horizon of a black hole. The work required to do this turns out to be mc2 and so the reaction force that the hovering cable wench feels must always be finite, right down to the event horizon. However, the tension in the bottom part of the cable attached to the lowered observer diverges and so it always snaps just prior to reaching it. Show that the tension in the bottom end of the cable near the event horizon a height h above it is given by

Problem 10.2.2

Use Eqn. 10.2.1 to find the weight felt by a 75 kg observer standing 100m over the event horizon of a 3 solar mass black hole.

___________________________________________________________________________________________

118 Chapter 10 The Schwarzschild Black Hole

10.3 "Apparently" Lighter With Speed

The point of this section is to demonstrate by calculating a case of motion how general relativity's predictions for motion from gravitation can be counterintuative when one's intuition is based on experience with Newtonian gravitation or even special relativistic dynamics. In this section we will look at the behavior of a test object thrown up or down in a Schwarzschild spacetime from the perspective of a hovering observer. If the hovering observer and the object are far from the hole then the result for the coordinate acceleration will be shown to be

a1 = -(GM/r2)[1 - (v2/c2)]

(10.3.1)

Note that at high radial speeds where v2/c2 can't be neglected, the object acts as if its gravitational mass shifts down from its inertial mass. In fact, with their definitions as made below they both shift up from m which is an invariant, but Mi as defined below shifts up more, making is appear as though gravity has less hold at higher radial speeds.

To start the process we find the Schwarzschild interval for general relativity in the hovering observer's coordinates. There are several coordinate transformations one might choose from to represent a transformation to a hovering observer's frame. Any will work that reduce the interval to the interval for special relativity at the location of the hovering ship. One might choose the transformation for its own simplicity. However, this increases the complexity of the global form of the invariant interval. Here we choose a transformation to a hovering ship frame which keeps the interval in simple form. The transformation is

t = t'(1 - 2GM/Rc2)-1/2

ò r' [(1 - 2GM/Rc2)/(1 - 2GM/r'c2)]1/2dr' = ò r (1 - 2GM/rc2)-1/2dr

(10.3.2)

The integration constant is chosen so that r = r' at R.

This transformation globally transforms the form of the Schwarzschild solution of general relativity into

(Note the lack of primes on the first and last r.) (10.3.3)

The metric components in the following expressions are then taken from this. We then look at the expression for coordinate acceleration Eqn. 5.3.8 in the absence of four-forces.

al = - Glmnumun + (ul/c)G 0mn umun

 

10.3 "Apparently" Lighter With Speed 119

The only nonzero ul are

u0 = c

u1 = v

And we are only interested in a1 so it becomes

a1 = - G111v2 - 2G101cv - G 100c2 + (v/c)(G011v2 + 2G001cv + G000c2)

Of these the only nonzero affine connections are

G111 = (1/2) g11(g11,1)

G100 = - (1/2)g11(g00,1)

G001 = (1/2) g00(g00,1)

These reduce it to

a1 = - (1/2)g11(g11,1)v2 + (1/2) g11(g00,1)c2 + g00(g00,1)v2

Simplified

a1 = (1/2){(1/g11)(g00,1)c2 + v2[2(1/g00)g00,1 - (1/g11)g11,1]}

We work out the metric derivatives to be

g00,1 = (dg00/dr)(dr/dr') = (2GM/r2c2)(1 - 2GM/rc2)1/2/[(1 - 2GM/Rc2)(1 - 2GM/r'c2)]1/2

g11,1 = - (1 - 2GM/Rc2)(2GM/r'2c2)/(1 - 2GM/r'c2)2

After insertion of these and g00 and g11 and simplification, this results in

a1 = -(GM/r2){( 1 - 2GM/r'c2)1/2(1 - 2GM/rc2)1/2/(1 - 2GM/Rc2)3/2 - (v2/c2)[2(1 - 2GM/Rc2)1/2/[(1 - 2GM/rc2)1/2(1 - 2GM/r'c2)1/2] - (r/r')2/(1 - 2GM/r'c2)]}

(10.3.4)

This is the exact solution.

Next we might look at approximations.

First we might look at the approximation where the ball is instantaneously at the location of the hovering ship. (r = r' = R) At this instant, it becomes

a1 = -(GM/R2){1/(1 - 2GM/Rc2)1/2 - (v2/c2)[2/(1 - 2GM/Rc2)1/2 - 1/(1 - 2GM/Rc2)]}

(10.3.5)

 

120 Chapter 10 The Schwarzschild Black Hole

There are two different approximations of interest to make from here.

First we might let the speed of the ball instantaneously be at v = 0 at which moment it becomes:

a1 = -(GM/R2)/(1 - 2GM/Rc2)1/2

(10.3.6)

This form is expected as the observer is held still considering Eqn. 10.2.1

|F| = (1 - 2GM/rc2)-1/2GMm/r2

And we should expect a1 = |F|/m. For v = 0.

Second, if we go back to Eqn .10.3.5 and make an approximation where both the observer and the ball are far from the hole, then it becomes Eqn. 10.3.1

a1 = -(GM/r2)[1 - (v2/c2)]

At high radial speeds where v2/c2 can't be neglected, the object acts as if its gravitational mass shifts down from its inertial mass.

Merely to demonstrate this oddity, consider the following. Recall from special relativity that when an ordinary force is applied in the direction of motion we have Eqn. 3.2.11

f = g3ma

The Newtonian gravitational mass Mg is given by Eqn. 4.1.1

f = - GMMg/r2

This results in

- GMMg/r2 = g3ma

Now insert the acceleration from Eqn. 10.3.1 and it becomes

- GMMg/r2 = - g3m(GM/r2)[1 - (v2/c2)]

This results in

Mg = gm

(10.3.7)

If we think of inertial mass as the proportionality between ordinary force and ordinary acceleration (which we don't typically do), then the inertial mass is given by

 

10.3 "Apparently" Lighter With Speed 121

Mi = g3m

(10.3.8)

At high radial speeds then, gravitational and inertial mass are not equivalent. They are related by

Mg = (1 - v2/c2)Mi

(10.3.9)

Here we see that the object does behave as if its gravitational mass shifts below its inertial mass at high radial speed.

Exercises

Problem 10.3.1

What would Eqn.10.3.8 become for motion perpendicular to the ordinary force applied. If 10.3.7 were to remain the same, what would the relationship between the new Mi and Mg be?

Problem 10.3.2

According to Eqn. 10.3.1, how fast would something have to move radialy in order to have half the accleration that it would have staying stationary?

___________________________________________________________________________________________

122 Chapter 10 The Schwarzschild Black Hole

10.4 Behavior of Light in a Schwarzschild Spacetime

For this section on general relativity, first lets derive the equation for the gravitational red shift for a Schwarzschild space-time. Then we will compare deflection of light according to a local observer to deflection over large trajectories, then derive the photon sphere and finally gravitational slowing of the remote coordinate speed of light known as the Shapiro effect.

Starting with the interval for the metric for the Schwarzschild solution of general relativity we have Eqn.10.1.1

Consider a stationary observer so that the spatial displacements are zero and the interval is the proper time for this observer's world line. This reduces the expression to

dct2 = (1 - 2GM/rc2)dct2

or

dt = dt(1 - 2GM/rc2)-1/2

(10.4.1)

Now if we were to relate the observed periods of light that two different stationary observers at two different altitudes find coming from a common source for general relativity we get

T1(1 - 2GM/r1c2)-1/2 = T2(1 - 2GM/r2c2)-1/2

(10.4.2)

Using that frequency is the inverse of the period we arrive at an expression relating the frequencies observed

(f1)-1(1 - 2GM/r1c2)-1/2 = (f2)-1(1 - 2GM/r2c2)-1/2

or

f1(1 - 2GM/r1c2)1/2 = f2(1 - 2GM/r2c2)1/2

(10.4.3)

Sometimes a Taylor expansion is done at this point where we keep only terms to first order in 1/r for an approximation that is a simpler expression and we then have

f1(1 - GM/r1c2) » f2(1 - GM/r2c2)

(10.4.4)

This phenomenon in general relativity is called gravitational red shift.

 

10.4 Behavior of Light in a Schwarzschild Spacetime 123 

Next lets look at a case of deflection of light as observed locally from inside a high hovering ship. We will find that this amount which is what is referred to as the amount of deflection due to equivalence is only half the value of deflection over large distances. That's the curvature of space effect. Imagine that a ship hovers above a planet, star, or Schwarzschild black hole at a distance to the center of "r" which we will take to be large compared to the dimensions of the ship. We orient a laser so that it points at the center of a target in a direction perpendicular to the direction of the massive body. We will show for general relativity that the light is deflected so that it hits below target as long as the ship hovers still by demonstrating that

ar = (c2/r) - GM/r2.

(10.4.5)

We start with the equation for coordinate acceleration Eqn. 5.3.8

al = (dt/dt)2[Fl - (ul/c)F0]/m - Glmnumun + (ul/c)G0mnumun

In this case there is no four-force, as none act on the photons, it is

al = - Glmnumun + (ul/c)G0mnumun

The component we need is

ar = - G rmnumun + (u r/c)G0mnumun

124 Chapter 10 The Schwarzschild Black Hole

Then we make an approximation what for the entire length of the beam ur << c.

ar = - G rmnumun

Inserting the expression for the affine connection we have

ar = -(1/2)grr(gm r,n + gn r,m - gm n,r)umun

(no sum on r as its not a variable index)

For Simplicity we'll let the beam be oriented in the f direction at q = p /2. Doing the sums we have

ar = (1/2)grr(gff,r)uf uf - (1/2)grr(grr,r)urur + (1/2)grr(gctct,r)uctuct

Using grr = -1/(1 - 2GM/rc2) and gctct = 1 - 2GM/rc2 we have

ar = (1/2)grr(gff,r)ufuf - grr[(GM/r2c2)/(1 - 2GM/rc2)2]urur + grr(GM/rc2)uctuct

10.4 Behavior of Light in a Schwarzschild Spacetime 125

Now we make the approximations ur << c and uf = c/r for the entire length of the beam and using gff = -r2sin2q = -r2 and r >> 2GM/c2 we have

ar = -(1/2)(-2r)(c2/r2) - (GM/r2c2)c2

Or more simply Eqn. 10.4.9

ar = (c2/r) - GM/r2

The first term c2/r arises solely due to using spherical coordinates. If there were no mass and we chose to use spherical coordinates to describe the rectilinear motion of an object moving in that direction we would still have a v2/r term. The other term -GM/r2 we note is identical to the Newtonian expression for gravitation. This tells us that if the ship itself were to have been in free fall, the beam would have hit dead center. But that is what we would also expect for a ship in an inertial frame in the absence of massive bodies.

We found that light deflects over short distance in a way consistent with Newtonian gravitation over a short distance above,

however the deflection of light over large distances we will show here to differ from Newtonian gravitation by a factor of 2. It is this general relativity prediction that agrees with astronomical observation. That is experimental proof for the curvature of the space.

From equation 10.1.12 considering a nonzero angular momentum there will be a minimum radius the light approaches the gravitating mass at which the equation yields

(10.4.6)

From this the angular momentum parameter can be solved for in terms of the energy parameter

(10.4.7)

Inserting this into equation 10.1.15 results in

(10.4.8)

Light speed particles are described by this as the limit as g ® ¥ resulting in

(10.4.9)

It is a strait forward back check to verify that neglecting higher order terms than GM/rmin2c2 the following satisfies that differential equation

(10.4.10)

At the angles at which the light comes in from and goes out to infinity u then goes to zero. This yields a quadratic equation in sinf resulting in

(10.4.11)

Since sinf must be less than 1 in magnitude it is the top sign that is the correct solution. This can then be written

(10.4.12a,b,c)

which yields

(10.4.13)

And for a small angle of deflection this yields

(10.4.14)

 

126 Chapter 10 The Schwarzschild Black Hole

The incoming deflection angle is equal to the outgoing deflection angle so the sum of the two giving the total deflection is twice that value:

(10.4.15)

It is the value of this prediction that matches the deflection of light from stars passing our sun on the way to us and results in the correct gravitational lenzing observed in nature.

Finally lets derive the photon sphere. The photon sphere of a Schwarzschild black hole is a sphere given by a radius at which a photon can make a complete closed orbit around the black hole.

rps = 3GM/c2.

(10.4.16)

In this section we will prove this.

When we use the coordinate variables for the indices no Einstein summation will be implied.

We begin with the expression for coordinate acceleration Eqn. 5.3.8

al = (dt/dt)2[Fl - (ul/c)F0]/m - Glmnumun + (ul/c)G0mnumun

No four forces will act on the photon leaving us with

al = - Glmnumun + (ul/c)G0mnumun

For simplicity we will consider the circular orbit, ur = 0, that is at the equator q = p/2 leaving us with

ar = 0 = - Grctctuctuct - 2Grctfuctuf - Grffufuf

(10.4.17)

We have already seen that the coordinate speed will be given by

vW = (1 - 2GM/rc2)1/2c = ruf

0 = - Grctctc2 - 2Grctf (1 - 2GM/rc2)1/2c2/r - Grff(1 - 2GM/rc2)c2/r2

(10.4.18)

Now we consider the affine connections for general relativity

Grctct = -(1/2)grrgctct,r = (1 - 2GM/rc2)GM/c2r2

Grff = -(1/2)grrgff,r = -(1 - 2GM/rc2)r

Grctf = 0

(10.4.19)

Inserting into Eqn. 10.4.12 these we have

0 = - c2(1 - 2GM/rc2)GM/c2r2 + (1 - 2GM/rc2)2c2/r

Now factor

0 = [- GM/r2 + (1 - 2GM/rc2)c2/r](1 - 2GM/rc2)

simplified

0 = (1 - 3GM/rc2)(1 - 2GM/rc2)

(10.4.20)

We have two possible solutions.

One is Eqn.10.1.5

r = 2GM/c2

and the other is Eqn 10.4.10

r = 3GM/c2

(10.4.21)

The first is the Schwarzschild radius. The second is the correct solution for the photon sphere.

Next lets look at the remote observer frame coordinate gravitational slowing of the speed of light which, unlike special relativity which uses globally rectilinear Lorentz frames, varies remotely. Refer again to Eqn. 10.1.1

For general relativity for a lightlike path ds = 0 and so dividing through this equation by dt2 we have an expression for the radial and angular components of the coordinate speed of light.

0 = (1 - 2GM/rc2)c2 - vr2/(1 - 2GM/rc2) - vW2

or more simply

vr2 + (1 - 2GM/rc2)vW2 = (1 - 2GM/rc2)2c2

(10.4.22)

From this we see that the coordinate speed of light near a black hole depends on the direction in which it travels. For light moving radialy away from the hole this reduces to

vr = ±(1 - 2GM/rc2)c

(10.4.23)

For instantaneously moving perpendicularly to the radial vector to the hole the speed is

vW = ±(1 - 2GM/rc2)1/2c

(10.4.24)

Lets now take a closer look at the coordinate speed for radial moving light.Eqn.10.4.6

vr = ± (1 - 2GM/rc2)c

As we will discuss in the section on wormholes there are actually two interior regions of a Schwarzschild spacetime of general relativity. The sign we choose below is chosen to indicate an inward direction of travel for light in the black hole interior region.

This is also our exterior region's solution representing outgoing light.

vr = (1 - 2GM/rc2)c

From this equation we find that the coordinate speed of light exceeds c close to the center of the hole. In fact we find that for

r < GM/c2

(10.4.25)

The coordinate speed of radialy moving light is greater than c.

In order to experimentally observe this Shapiro effect sending signals between far distant space probes we have to derive the equation of motion for light for experimental comparison to the theory for a more arbitrary geodesic trajectory because we can not set them hovering over the sun at constant radial position. So first go back to equations 10.1.6, 10.4.7, and 10.1.10

Inserting the first two into 10.1.10 results in

 

(10.4.26)

Algebra

(10.4.27)

Light is described by the limit as g ® ¥ . So this reduces to

(10.4.28)

Simplified

(10.4.29)

This first order differential equation is separable so the time it takes according to a remote observer for light to go from the high position r=a to the lowest position r=rmin corresponding to the minus sign if we switch the limits to drop the sign is given by

(10.4.30)

Doing some expansion and keeping only terms to first order in GM/c2

(10.4.31)

Its a strait forward differentiation to back check that the following is the solution to that integral

(10.4.32)

(10.4.33)

Going from 10.4.36 to 10.4.37 we will neglect terms on the order (rmin2/a2) so the first term of 10.4.33 becomes what the flat spacetime prediction would become, so the Shapiro delay for this part of the trip is

(10.4.34)

If we then find the Shapiro delay for the light traveling up to some higher place r=b on the other side, that would be

(10.4.35)

giving us a one way trip delay from a to b of

(10.4.36)

Now if we do the experiment between two planets near superior conjunction, rmin will be small compared to both a and b reducing this to

(10.4.37)

Now if the signal goes for a round trip during which the planets don't significantly change their relative positions with respect to each other the total Shapiro delay will be

 

(10.4.38)

In some big texts like "General Relativity" by Wald, the Shapiro delay is defined in terms of Schwarzschild time as above. However some like "Gravitation" by Misner Thorne and Wheeler defines it in terms of time according to the lab. If you're not going to convert your labs time values from experiments to Schwarzschild time then you have to adjust this result with systematic error correction parameters to account for things such as gravity time dilation of earth near the sun, time dilation moving around the sun, earth's gravity time dilation on the lab, time dilation of lab moving as earth spins or even to account for things like signal lag through atmosphere. With systematic error correction parameters in place the equation in terms of lab time can be written (see problem 10.4.6) :

(10.4.39)

Notice that since this is proportional to GM/c2, this highest order delay term is completely relativistic. As such Newtonian gravitation not only can not account for it, but since a Newtonian acceleration field would cause everything to speed up going by the sun by |a| = GM/r2,

Treating the photon as obeying Newtonian gravitation particle dynamics you would get:

(10.4.40a-d)

Which comparing with no sun present in approximation results in a round trip difference of

 

(10.4.41)

Newtonian gravity predicts the wrong sign completely expecting an early time of arrival for the light instead of a delay. Experiments such as the Earth-Venus time delay measurement that first experimentally confirmed the effect in the early '70s really is the clincher for the validity of general relativity as compared to Newtonian gravitation. The theories make opposite predictions here and it was general relativity that turned out to be right.

 

Exercises

Problem 10.4.1

Use small number approximation to find the change in frequency a locally 655nm wavelength source undergoes rising 15.5m above the surface of the earth.

Problem 10.4.2

Where is the coordinate speed of radial moving light (1/2)c? Where does this occur for tangential moving light?

Problem 10.4.3

Show that changing radial coordinate to r' where

r = r'(1 + GM/2r'c2)2

puts the Schwarzschild metric in to the isotropic coordinate expression

ds2 = [(1 - GM/2r'c2)/(1 + GM/2r'c2)]2dct2 - (1 + GM/2r'c2)4 [dr'2 + r'2dq2 + r'2sin2qdf2]

Problem 10.4.4

Lecture Part 1

Lecture Part 2

In isotropic spherical coordinates a good weak field approximation for a general static matter distribution is

where F(r,q,f) is the Newtonian gravitational potential for the matter distribution.

a. Show that this reduces to the Schwarzschild metric equation of problem 10.4.3 given F = -GM/r and h = 0.

b. Write this metric for Cartesian coordinates.

c. In Cartesian Coordinates, calculate the Einstein tensor with your choice of software and then find the cooresponding stress energy tensor keeping only terms to first order in F(x,y,z) and h(x,y,z) and their derivatives because products will be lower in order of magnitude for a weak field approximation. Show that

T00~ (Ñ 2F/4pG)c2 and to show what px , py, and pz are in terms of partial derivatives of h.

Problem 10.4.5

Solution

a. Use the timelike Killing vector cooresponding to the time isometry in the metric of problem 10.4.4 to show that there is a conserved energy parameter of geodesic motion and use it with the metric of problem 10.4.4 to calculate (dr/dt)2 for general geodesic motion in the presence of a static matter distribution.

b. Show that if the Potential F(r,q,f) is indeed weak that the resulting geodesic motion calculation for (dr/dt)2 indeed matches the calculation for Newtonian gravitation.

Problem 10.4.6

Go back to equation 10.4.33 and follow thereafter showing that doing a time correction accounting for the lab being at the earth-sun distance leads to the sign difference on the first term in the brackets between equations 10.4.38 and 10.4.39. If all other corrections are small d1 and d2 are about 1.

Return to Modern Relativity